But there are so many more interesting ways to apply the self same math.liquidat0r wrote:
That's what Physics is, no? At least in kinematics, anyway. It's applying maths to solve problems identical to these ...Jenspm wrote:
Trying to put physics into those kind of real life situations ftl.
Yes it is, but most of the dumb word problems are too long and drawn out.liquidat0r wrote:
That's what Physics is, no? At least in kinematics, anyway. It's applying maths to solve problems identical to these ...Jenspm wrote:
Trying to put physics into those kind of real life situations ftl.
Ok, I need more help lol. This physics homework is making me mad. I swear I have the right answer, but obviously it isn't because when I type it in it says it's wrong.
A car with an initial speed of 23.2 km/h ac-
celerates at a uniform rate of 0.86 m/s2 for 4.7
s.
a) Find the final speed of the car. Answer
in units of m/s.
002 (part 2 of 2) 10.0 points
b) Find the displacement of the car after that
time. Answer in units of km.
For A I got 27.242 km/h
For B I got 118.5387 km
A car with an initial speed of 23.2 km/h ac-
celerates at a uniform rate of 0.86 m/s2 for 4.7
s.
a) Find the final speed of the car. Answer
in units of m/s.
002 (part 2 of 2) 10.0 points
b) Find the displacement of the car after that
time. Answer in units of km.
For A I got 27.242 km/h
For B I got 118.5387 km
Speed is 280/6.74.Whiplash wrote:
A student wanted to drive from Austin to
San Antonio, 80 miles south of Austin on
highway I35. Unfortunately, he entered the
highway in the wrong direction and drove all
the way toWaco — 100 miles north of Austin
— before he noticed his error. In Waco,
he turned around, drove back to Austin and
continued to San Antonio. The whole trip
took 6.74 hours.
What was the student’s average speed dur-
ing this trip? Answer in units of MPH.
011 (part 2 of 2) 10.0 points
What was the student’s average velocity dur-
ing his trip? Take your positive direction to
be southbound on I35. Answer in units of
MPH.
Ok, for the answer to number 11 I got 26.70623145, but it says that it's wrong. What am I doing wrong?
EDIT: answer = 41.543 mi/h
Velocity is 80/6.74
EDIT: answer = 11.8694 mi/h
Velocity is calculated based on displacement, which is the distance between your starting and ending points.
Last edited by Vub (2008-09-20 17:53:44)
For part A use v = u + a*t, u = 23.2/3.6 (gotta change the units to m/s).Whiplash wrote:
Ok, I need more help lol. This physics homework is making me mad. I swear I have the right answer, but obviously it isn't because when I type it in it says it's wrong.
A car with an initial speed of 23.2 km/h ac-
celerates at a uniform rate of 0.86 m/s2 for 4.7
s.
a) Find the final speed of the car. Answer
in units of m/s.
002 (part 2 of 2) 10.0 points
b) Find the displacement of the car after that
time. Answer in units of km.
For A I got 27.242 km/h
For B I got 118.5387 km
EDIT: answer = 10.4864 m/s OR 37.7512 km/h
For part B use s = u*t + 0.5*a*t^2 (again u=23.2/3.6)
EDIT: answer = 39.78758889 m OR 0.03978758889 km
Last edited by Vub (2008-09-20 17:57:03)
Danget, I forgot to change the units. Thanks =PVub wrote:
For part A use v = u + a*t, u = 23.2/3.6 (gotta change the units to m/s).Whiplash wrote:
Ok, I need more help lol. This physics homework is making me mad. I swear I have the right answer, but obviously it isn't because when I type it in it says it's wrong.
A car with an initial speed of 23.2 km/h ac-
celerates at a uniform rate of 0.86 m/s2 for 4.7
s.
a) Find the final speed of the car. Answer
in units of m/s.
002 (part 2 of 2) 10.0 points
b) Find the displacement of the car after that
time. Answer in units of km.
For A I got 27.242 km/h
For B I got 118.5387 km
EDIT: answer = 10.4864 m/s OR 37.7512 km/h
For part B use s = u*t + 0.5*a*t^2 (again u=23.2/3.6)
EDIT: answer = 39.78758889 m OR 0.03978758889 km