Need to draw graphic y=2ln x. But how to calculate assets? Any help would be appreciated!
Last edited by Markooo*Est (2008-12-15 13:59:19)
y = 2lnx is just a strech of y = lnx by SF 2 parallel to the y axis.Markooo*Est wrote:
Need to draw graphic y=2ln x. But how to calculate assets? Any help would be appreciated!
Not sure about assets
Graph of y = ln(x)
There are calculators that draw graphs. You just put equations in.
1 is the x intercept if that's what you mean
link plz?.Sup wrote:
There are calculators that draw graphs. You just put equations in.
TI 83 +Markooo*Est wrote:
link plz?.Sup wrote:
There are calculators that draw graphs. You just put equations in.
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TI 89 Titanium tbqh
i need a program not calculator!
I'm just that oldschool that I still used the 83+. At the time it was the best calculator that I could use for the IB finals
once upon a midnight dreary, while i pron surfed, weak and weary, over many a strange and spurious site of ' hot xxx galore'. While i clicked my fav'rite bookmark, suddenly there came a warning, and my heart was filled with mourning, mourning for my dear amour, " 'Tis not possible!", i muttered, " give me back my free hardcore!"..... quoth the server, 404.
the 84's just an 83 with a streamlined skinmax wrote:
I'm just that oldschool that I still used the 83+. At the time it was the best calculator that I could use for the IB finals
and sligihtly improved software (discontinuities are actually discontinuities and don't get connected by the calculator)
Search graphing calculator on google to find an internet program that will do it for you.
He makes a convincing argument....
It looks like this
Only times 2, so that at any point along the line its y value is equal to the value in that picture x 2
I r have TI-89 Titanium and I still don't know how to use most of the functions
Okay I got this mathproblem:
I know (8x-4)*(8x+4) isn't the correct answer, because some number has to be at the postion of A: A(...)(...)
Help please?
I know (8x-4)*(8x+4) isn't the correct answer, because some number has to be at the postion of A: A(...)(...)
Help please?
pffff, we use PC programs, so much bettermax wrote:
TI 83 +Markooo*Est wrote:
link plz?.Sup wrote:
There are calculators that draw graphs. You just put equations in.
erhBroodbeleg wrote:
Okay I got this mathproblem:
http://amaple.science.uva.nl:8081/tmp/e … ckakok.gif
I know (8x-4)*(8x+4) isn't the correct answer, because some number has to be at the postion of A: A(...)(...)
Help please?
(8x - 4) x (8x + 4) = 64x^2 + 32x - 32x - 16
32x - 32x = 0
Therefore
64x^2 - 16 = (8x-4)*(8x+4)
oooh, you mean like that
Take 16 outside
16(4x^2 - 1)
ie:
16 x (2x - 1) x (2x + 1)
Last edited by Sydney (2008-12-19 07:41:37)
You guys are fucking nerds.
And you're fucking stupid. Go figure.Sir Schmoopy wrote:
You guys are fucking nerds.
Last edited by Jenspm (2008-12-19 07:43:22)
Bow, chicka, wow, wow.Jenspm wrote:
And you're fucking stupid. Go figure.Sir Schmoopy wrote:
You guys are fucking nerds.
Okay, same kind of "problem"
I don't see how it's done and the answer has to be, again, like A(...)(...).
And Sydney, i see what you did with the other one, but i don't think i can get 81 out of it and put it for A?
I don't see how it's done and the answer has to be, again, like A(...)(...).
And Sydney, i see what you did with the other one, but i don't think i can get 81 out of it and put it for A?
Last edited by Broodbeleg (2008-12-19 07:52:56)
(4z-9)^2
edit - I don't get what you mean with this A(...)(...) stuff.... I'm pretty sure what I did there ^ is what you want...
edit - I don't get what you mean with this A(...)(...) stuff.... I'm pretty sure what I did there ^ is what you want...
Last edited by Jenspm (2008-12-19 07:57:59)
He means that there needs to be one string in front of the variables, look at my post above.Jenspm wrote:
(4z-9)^2
edit - I don't get what you mean with this A(...)(...) stuff.... I'm pretty sure what I did there ^ is what you want...
Okay, did some thinking and thought maybe this is a possible solution?
81*((16/81)z^2 - (72/81)z+1)
Nope, isnt correct.
81*((16/81)z^2 - (72/81)z+1)
Nope, isnt correct.
Last edited by Broodbeleg (2008-12-19 08:08:08)