SplinterStrike
Roamer
+250|6846|Eskimo land. AKA Canada.
d) 2/3 times x minus 17/6 = 5/2
so x(2/3)= 5/2 +(17/6)
x(2/3) =(15/6)+(17/6)
x(2/3)= 5 and 1/3
x= 5 and 1/3 divided by 2/3
x= 8

I forgot to change my minus earlier

the answer is 8

Last edited by SplinterStrike (2006-12-13 11:19:11)

Zimmer
Un Moderador
+1,688|7191|Scotland

No, look closely, I "x" the "6" on the other side.
I am completely confused.
SplinterStrike
Roamer
+250|6846|Eskimo land. AKA Canada.
To calculate your triangles, you need to know about Pythagore's triangle. Do you know this?
mtb0minime
minimember
+2,418|7089

(2/3)x - (17/6) = (5/2)
(2/3)x = (15/6) + (17/6)
(2/3)x = (32/6)
x = (3/2)(32/6)
x = (16/2) = 8

and in case you missed my reply the first time...

1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters

Last edited by mtb0minime (2006-12-13 11:22:23)

SplinterStrike
Roamer
+250|6846|Eskimo land. AKA Canada.

zimmer92 wrote:

No, look closely, I "x" the "6" on the other side.
I am completely confused.
Zimmer, if you're gonna multiply, you need to multiply on both sides of the equation. in yours, you only multiplied on the right side (the 5/2) but not the left(the 2/3)
sneakysegan11
Member
+13|6979|York, PA

mtb0minime wrote:

(2/3)x - (17/6) = (5/2)
(2/3)x = (15/6) + (17/6)
(2/3)x = (32/6)
x = (3/2)(32/6)
x = (16/2) = 8

and in case you missed my reply the first time...

1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters
Ok, I am going by what you gave me. Anybody else argue with these answers?
1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters
Zimmer
Un Moderador
+1,688|7191|Scotland

Shit, I fail at maths. Hmmmmmmmmmmmmmm. I went wrong somewhere. Wait....I went wrong everywhere.

Why did you get suspended naughty little boy?
Zimmer
Un Moderador
+1,688|7191|Scotland

SplinterStrike wrote:

zimmer92 wrote:

No, look closely, I "x" the "6" on the other side.
I am completely confused.
Zimmer, if you're gonna multiply, you need to multiply on both sides of the equation. in yours, you only multiplied on the right side (the 5/2) but not the left(the 2/3)
Phew, I forgot to do that. I thoguht something was seriously wrong with my brain there.
sneakysegan11
Member
+13|6979|York, PA

zimmer92 wrote:

Shit, I fail at maths. Hmmmmmmmmmmmmmm. I went wrong somewhere. Wait....I went wrong everywhere.

Why did you get suspended naughty little boy?
hahaha, this little freshman was fucking with my brother and calling him names and threatining to beat him up. So I just beat him up a little (He had to go to the hospitol and get 15 stiches next to his eye and he got a broken jaw) You know nothing major!!!
SplinterStrike
Roamer
+250|6846|Eskimo land. AKA Canada.

heggs wrote:

by the way this is a cake walk. i'll set you up, but i won't finish them. you've heard of SOHCAHTOA right?
you may need to study a bit if you're running into trouble with this stuff.

D) first of all, add the 17/6 to 5/2 on the right side. divide by 2/3 to solve for x. this problem had nothing to do with trig.

G) sin 57 = 239/x

H) tan y = 36.8/22

2. draw a triangle. tan32.8 = x/40.

3. same triangle as (2). sin64 = x/65
eh heggs has set you up right here. These are all right. Complete these and you're golden.
Snowmanimal
Not so unique forum title
+30|6978|My head

sneakysegan11 wrote:

MorbiD.ShoT wrote:

zimmer92 wrote:

How did you get that?
2/3x - 17 = 5/2 x 6
2/3x - 17 = 15
2/3x = 32
2x = 96
x = 48
Look at mine.
so is it 8 or 48?
Try using parantheses

2/3x -17/6 = 5/2
so
4/6x - 17/6 = 15/6
so
4/6x = 15/6 + 17/6
so
4/6x = 32/6
(6/4)(4/6)x = (32/6)(6/4)
**** (6/4)(4/6) cancels out and the 6s cancel out here (32/6)(6/4)****
so
x= 32/4
so
x=8


plug 8 into the calculator to check
((2/3)(x)) - 17/6 = 2.5 (or 5/2)

check
done

Last edited by Snowmanimal (2006-12-13 11:27:13)

Enzzenmachine
Member
+20|6780

zimmer92 wrote:

Snowmanimal wrote:

d. = 8
How did you get that?
2/3x - 17 = 5/2 x 6
this step is wrong.

(2/3)x - (17/6) = (5/2) <=> (2/3)x = (5/2) + (17/6) <=> x = (32/6) / (2/3) <=> x = 8



as mtb0minime said..
sneakysegan11
Member
+13|6979|York, PA

SplinterStrike wrote:

heggs wrote:

by the way this is a cake walk. i'll set you up, but i won't finish them. you've heard of SOHCAHTOA right?
you may need to study a bit if you're running into trouble with this stuff.

D) first of all, add the 17/6 to 5/2 on the right side. divide by 2/3 to solve for x. this problem had nothing to do with trig.

G) sin 57 = 239/x

H) tan y = 36.8/22

2. draw a triangle. tan32.8 = x/40.

3. same triangle as (2). sin64 = x/65
eh heggs has set you up right here. These are all right. Complete these and you're golden.
so do i just put that into the calculator to get the answers? I can find a calculator online
Snowmanimal
Not so unique forum title
+30|6978|My head
remember SOH, CAH, TOA
mtb0minime
minimember
+2,418|7089

Trig = easy shit. I took my differential equations final yesterday. You guys wanna try problems like:

Given the matrix
      -2  1  -1
A = 1  -3  0
      3  -5  0

i) find the eigenvalues
ii) for each eigenvalue find the algebraic and geometric multiplicities
iii) for each eigenvalue [lambda] find the smalles integer k such that the dimension of the nullspace of (A - [lambda]I)^k is equal to the algebraic multiplicty
iv) for each eigenvalue find q linearly independent generalized eigenvectors, where q is the algebraic multiplicity
v) verify that the collection of the generalized eigenvectors you find in part iv for all of the eigenvalues is linearly independent
vi) find a fundamental set of solutions for the system y' = Ay

Or how about...

given

y'' + 3y' + 2y = 3e^(-4t) , y(0) = 1, y'(0) = 0

find the homogenous equation, and then find the particular solution. Use these to find the general solution. Then find the solution satisfying the particular given initial conditions.

Cheers
sneakysegan11
Member
+13|6979|York, PA
GUYS! Remember that I wasnt in school when he taught this so I have no clue what anything your saying is!!!
mtb0minime
minimember
+2,418|7089

Haha I know I'm just messing with ya! Do you still need to find out how to set up those problems? I could start typing them up in word or something.
sneakysegan11
Member
+13|6979|York, PA
1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters

^^^^^^^^^^^ Are these answers right? Can anybody help me out and check these answers? Cause i need them all to be right this is a 200 point quiz

Last edited by sneakysegan11 (2006-12-13 11:33:15)

SplinterStrike
Roamer
+250|6846|Eskimo land. AKA Canada.

sneakysegan11 wrote:

mtb0minime wrote:

(2/3)x - (17/6) = (5/2)
(2/3)x = (15/6) + (17/6)
(2/3)x = (32/6)
x = (3/2)(32/6)
x = (16/2) = 8

and in case you missed my reply the first time...

1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters
Ok, I am going by what you gave me. Anybody else argue with these answers?
1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters
I would contest the 1b). I found 60.4o
sneakysegan11
Member
+13|6979|York, PA
Ok, Good enough, thanks to everybody!!! I'll give whoever helped some karma!!! THanks!
sneakysegan11
Member
+13|6979|York, PA

SplinterStrike wrote:

sneakysegan11 wrote:

mtb0minime wrote:

(2/3)x - (17/6) = (5/2)
(2/3)x = (15/6) + (17/6)
(2/3)x = (32/6)
x = (3/2)(32/6)
x = (16/2) = 8

and in case you missed my reply the first time...

1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters
Ok, I am going by what you gave me. Anybody else argue with these answers?
1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters
I would contest the 1b). I found 60.4o
60.4 is right> how do you put a degrees symbol?
Marinejuana
local
+415|7020|Seattle
this looks like a great opportunity to procrastinate but i really shouldnt. Sorry!
Superior Mind
(not macbeth)
+1,755|7127
yeah, all of those problems can be solved with a scientific calculator, just so you know. If you don't have one get one.
mtb0minime
minimember
+2,418|7089

Ok, 1b answers are different because I used radians because the angle was not given as degrees (if there is no degree symbol and it's simply a number, then it's measured in radians). When calculating it, make sure your calculator is in radians.


Also, here's the setups for the other problems...

https://img201.imageshack.us/img201/1531/untitledwr3.png

Last edited by mtb0minime (2006-12-13 11:48:06)

SplinterStrike
Roamer
+250|6846|Eskimo land. AKA Canada.

sneakysegan11 wrote:

SplinterStrike wrote:

sneakysegan11 wrote:


Ok, I am going by what you gave me. Anybody else argue with these answers?
1b) 1.0541
1d) 8
1g) 284.9748 feet
1h) 59.1279 degrees
2) 25.5614 feet
3) 58.4216 meters
I would contest the 1b). I found 60.4o
60.4 is right> how do you put a degrees symbol?
Hehe BBCode superscript. I just put the letter O in superscript.

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