BF2S Forums Proof that math are false !

how is this even a problem?

$25 plus $3 returned = $28, $28 + $2 = $30

they never pay $27 or $9. they always pay $25 or $8.3 each. $8.3 x 3 = 25

the missing dollar is the .3 x 3 and we know that they still have $1 in their pocket each and the other guy has $2.

Last edited by twiistaaa (2007-06-27 03:34:33)

x never changes though...

elstonieo wrote:

weasel_thingo wrote:

a better way to prove math wrong is teh 0.99999999 reocuring =1
       .
x=0.9  .         x10
10x=9.9        -x
9x=9             /9
1x=1
                                                                                            .
the reason why that is wrong i think is because you are using 0.9 as a finite value, someone fill me in on this.

.                                                                                 .
arnt you forceing the equation by taking off the number .9  and not keeping it as x

             .                     .
10x = 9.9                 -0.9
          .   
10x-0.9 = 9               /10
          .                         .
x - 0.09 = 0.9         +0.09
           .         .
x = 0.99  = 0.9

------
as soon as we change the x on one side of the eqaution we have to do it to the other side, otherwise all ans are false

I don't know what you've done to the equation here so I'll type it again for you
       .
x=0.9
          .
10x=9.9
                                        .    .
10x-x=9   in other words 9.9-0.9=9

9x=9 obviously because 10x-x=9x

divide both sides by nine gives x=1

The x never changes. I don't know what you did wrong.

petermassingale wrote:

Gawwad wrote:

weasel_thingo wrote:

yes it is about 1/3 that doesnt make it 1/3 so you cant use it in an equation as 1/3 and have teh exact correct answer.

....

replied to this already but it didn't show up on the thread for some reason.

I can't be arse to write it again so just go to this link and shut up.
This was discussed before and no need to get this thread closed over this.
http://en.wikipedia.org/wiki/0.9999999

Look at post #54

You're quick
Deleted 10 sec after posting!

This melon scratcher relies on wording to fool you and is not a case of maths going wrong.  It's pretty simple really, the last sentence (which supposedly highlights the miscalculation) works because the first figure it gives you is the three lots of $9 the people PAID (so not what they have got now) and the second figure that you add to those three 9s is the $2 the reception KEEPS for himself (so what he has in his possession and thus the opposite to the first figure). 

In other words you are adding together two figures that don't relate to each other and coming up with $29.  Keep the maths uniform and it all works out.  So if we only concentrate on what the subjects in the riddle actually have it comes back to $30.  So at the end:-

Hotel = $25
Receptionist = $2
3 Guys = $3 (1 dollar each)
Total $30

If you remember that the guys only have a dollar each at the end and forget that they paid $9 it all becomes clear.

Last edited by =OBS= EstebanRey (2007-06-27 06:33:32)

weasel_thingo wrote:

a better way to prove math wrong is teh 0.99999999 reocuring =1
       .
x=0.9  .         x10
10x=9.9        -x
9x=9             /9
1x=1
                                                                                            .
the reason why that is wrong i think is because you are using 0.9 as a finite value, someone fill me in on this.

Thats the failure of Newtonian math. Quantum math suggests that we can't know what .9999 equals because as the difference between .99999 and 1 is infinitesimally small the laws of physics and mathematics change. In newtoniam math there is no accomodation made for this affect and thus we must estimate .9999 as 1.

IntrebuloN wrote:

Gawwad wrote:

weasel_thingo wrote:

yes it is about 1/3 that doesnt make it 1/3 so you cant use it in an equation as 1/3 and have teh exact correct answer.

Do you understand infinity? I said aprox 0.3333 (0.333~) as I don't intend to write an infinite amount of 3's and I used it instead of 0.333...3 which means the same.

Now, as I'm getting tired of you and your uneducated logic, I give you this link, which I hope will educate you a bit and make you realise that 0.9999...9 is indeed 1.
http://en.wikipedia.org/wiki/0.9999999
I could find you more sources but I can't be arsed to so you're better off just accepting this one.

This was also discussed previously so to avoid this thread being closed I won't continue to discuss it.
If you still disagree with the facts, you go a head. I don't care about your knowledge anymore.

it's not 1 at all, but in real world maths, we say that it's so close it may as well be 1.

edit: which i see is what the guy above me just said

It is agreed on by mathematicians that 0.999...9 is 1.
As math is based on agreements, then it is truth.

Andoura wrote:

twiistaaa wrote:

how is this even a problem?

$25 plus $3 returned = $28, $28 + $2 = $30

they never pay $27 or $9. they always pay $25 or $8.3 each. $8.3 x 3 = 25

the missing dollar is the .3 x 3 and we know that they still have $1 in their pocket each and the other guy has $2.

look they all payd 10$ in 1st when the manager give them back 1$ each it means they payd 9$ ... wich is 9 * 3 = 27 then the manager took 2$ for him wich makes 27 + 2 = 29 !!!!


Dont try to change things lool

It amazes me how you still can't figure out the faults in your equation...

Edit: i don't see you logic though twiistaaa.
They paid 10 each
-> 30
Waiter finds out it was supposed to be 25 and gives each 1 back
-> they paid 9 (10-1) each = 27
Waiter takes the 2 'extra' they paid from the 27
-> 25
The 3 guys have 1 $ each (3) and the waiter has 2$
25$ (amount restaurant gets) + 3$ + 2$ = 30$

Last edited by Gawwad (2007-06-27 11:27:24)

Bertster7 wrote:

Andoura wrote:

twiistaaa wrote:

how is this even a problem?

$25 plus $3 returned = $28, $28 + $2 = $30

they never pay $27 or $9. they always pay $25 or $8.3 each. $8.3 x 3 = 25

the missing dollar is the .3 x 3 and we know that they still have $1 in their pocket each and the other guy has $2.

look they all payd 10$ in 1st when the manager give them back 1$ each it means they payd 9$ ... wich is 9 * 3 = 27 then the manager took 2$ for him wich makes 27 + 2 = 29 !!!!


Dont try to change things lool

What missing dollar?

They each payed $9, so the hotelier has $9+$9+$9=$27, the three men each have $1 of the remaining $3 that make it up to $30.

Why add the $27 to the $2? The $2 is already included in the $27.

And besides, if the waiter takes 2$ from 27$ how do you get 27 + 2 ???

Gawwad wrote:

weasel_thingo wrote:

Gawwad wrote:

1/3 = ~0.3333
1/3 + 1/3 + 1/3 = 1
->
0.33333 + 0.33333 + 0.33333 =1

That is it. You can't argue about mathematical truths.
This was discussed before in a 15 page long thred so just live with it!

0.3333 isnt 1/3
nuff said

Have you people ever even studied math?!
~0.3333 means that it recurs, thus the ~ as 'about'

0.9999...9 = 1 and YOU CANNOT PROVE IT WRONG WITH MATH.

End of discussion, I wont reply back as I should be working and if you don't get it now, you never will.

Edit: don't be smart ass about the 0.333's

We discussed this in that other thread, and in math 0.999~ = 1.
In Nature, 0.999~  =/=  1

Math is human made, not made by nature.



I believe that is the conclusion we came to last time.

Andoura, I would definitely consider another hobby.

Maybe watching paint dry or watch grass grow.  They may suit your mindset a little bit better.

Jenspm wrote:

We discussed this in that other thread, and in math 0.999~ = 1.
In Nature, 0.999~  =/=  1

Math is human made, not made by nature.



I believe that is the conclusion we came to last time.

Even in nature, 0.999~ =  1. There is no difference between nature and maths when nature incorporates math phenomenons. Why should the answer differ ? We have several algebric proofs that 0.999~ = 1. You probably think that 0.99~ =/= 1 in nature because its hard to find a phenomenon where 0.999~ exists. But when it is there, its 1 !

Gawwad wrote:

IntrebuloN wrote:

Gawwad wrote:

Do you understand infinity? I said aprox 0.3333 (0.333~) as I don't intend to write an infinite amount of 3's and I used it instead of 0.333...3 which means the same.

Now, as I'm getting tired of you and your uneducated logic, I give you this link, which I hope will educate you a bit and make you realise that 0.9999...9 is indeed 1.
http://en.wikipedia.org/wiki/0.9999999
I could find you more sources but I can't be arsed to so you're better off just accepting this one.

This was also discussed previously so to avoid this thread being closed I won't continue to discuss it.
If you still disagree with the facts, you go a head. I don't care about your knowledge anymore.

it's not 1 at all, but in real world maths, we say that it's so close it may as well be 1.

edit: which i see is what the guy above me just said

It is agreed on by mathematicians that 0.999...9 is 1.
As math is based on agreements, then it is truth.

jonsimon wrote:

weasel_thingo wrote:

a better way to prove math wrong is teh 0.99999999 reocuring =1
       .
x=0.9  .         x10
10x=9.9        -x
9x=9             /9
1x=1
                                                                                            .
the reason why that is wrong i think is because you are using 0.9 as a finite value, someone fill me in on this.

Thats the failure of Newtonian math. Quantum math suggests that we can't know what .9999 equals because as the difference between .99999 and 1 is infinitesimally small the laws of physics and mathematics change. In newtoniam math there is no accomodation made for this affect and thus we must estimate .9999 as 1.

Again, there are different branches of mathematics. If you are talking to someone who subscribes to the real numbers approach to math, he would agree with Gawwad. If you were talking to a student who studies math ancillary to science (physics, chemistry, etc.) he would tell you that jonsimon is right, as we need quantum math/mechanics to explain why shit happens.