Consider a curve of x(y^2)-x^(3)y=6.
The derivative is: (3(x^2)y-y^2) / (2xy-x^3)
I need to find when the derivative does not exist (tangent line vertical).
So far, as we only need to see if the denominator is 0, I set 2xy-x^3=0.
Then, I factored this to get x(2y-x^2)=0.
I know from here that when x=0, there is a vertical tangent line. However, I think there is more than that. What should I do to find the rest, or if I am doing this wrong, how do I solve it?
The derivative is: (3(x^2)y-y^2) / (2xy-x^3)
I need to find when the derivative does not exist (tangent line vertical).
So far, as we only need to see if the denominator is 0, I set 2xy-x^3=0.
Then, I factored this to get x(2y-x^2)=0.
I know from here that when x=0, there is a vertical tangent line. However, I think there is more than that. What should I do to find the rest, or if I am doing this wrong, how do I solve it?