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2007-02-20 23:02:20
devildogfo
Member
+32|6770|Camp Lejeune
So i entered solve(long expression=0,t) and received

t=3.1574113E-3*(@n4 + 30.943104E0)

3.157E-3 is a valid t (the long expression is a derivative, Im finding max/mins) but I know there are a lot more out there, and I think thats what (@n4 + 30.943104E0) is trying to tell me, but what the frick does it mean. Anyone know?
2007-02-20 23:11:52
jermyang
I've Seen the Saucers.
+38|7187|Norcal, usa
i always thought that stuff was like:

you put a trig function into a solver and you'd get liek

x = pi/4 + @n2asdfl;kj;zxlkvj;laskdjf;lsafj

dunno senor.
2007-02-20 23:15:35
some_random_panda
Flamesuit essential
+454|6838

devildogfo wrote:

So i entered solve(long expression=0,t) and received

t=3.1574113E-3*(@n4 + 30.943104E0)

3.157E-3 is a valid t (the long expression is a derivative, Im finding max/mins) but I know there are a lot more out there, and I think thats what (@n4 + 30.943104E0) is trying to tell me, but what the frick does it mean. Anyone know?
Differentiation...I did that last year, and don't remember the whole thing.

But why don't you graph the gradient (the differentiation) and use the Maximum and Minimum settings?

(under F5, Math, numbers 3 and 4.)
2007-02-20 23:51:30
devildogfo
Member
+32|6770|Camp Lejeune
Yeah, that would work also! I didn't think of doing that. I have a graph of the function using regular software, but out of curiousity I would still like to understand TIs notation there..Thanks though!
2007-02-20 23:52:56
Vub
The Power of Two
+188|6942|Sydney, Australia
Maybe for positive integers n?
2007-02-21 06:47:58
Rosemosis
Member
+1|6816
Beats me, but I played games on my TI-83.

 

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