BF2S Forums What's wrong with this? Answer = Karma

Bertster7 wrote:

Of course it is. A calculator can't deal with infinite answers. The doesn't stop it from being the case. 0 multiplied by infinity is also equal to 1 (which can be seen in delta functions - which have infinite height, zero width and an area of unity - I used to have to use them all the time for Fourier, Laplace and Z Transforms).

nope. any number, even infinity, multiplied by 0 is 0. If the text I bolded would be true, then a line (1d) which has infinite length would be a 2d figure. Not happening.

Also, a calculator could draw a mark for the infinite ( ∞ ), if your statement would be true

Last edited by DeathUnlimited (2007-04-02 14:02:23)

too_money2007 wrote:

DeathUnlimited wrote:

(x - 1)/(x - 1) = (x - 1)(x + 1)/(x - 1)

You can't divide by zero

Well, you technically can. 100/0 = 100, because you're not really dividing 100 by anything. Right?

divide anythig by 2, its half itself (100/2 = 50)
divide anything by 1, it's itself (100/1 = 100)
divide anything by 0 its infinity (100/0 = Infinity)

That's were your shit goes wrong

Bertster7 wrote:

DeathUnlimited wrote:

Bertster7 wrote:

Of course it is. A calculator can't deal with infinite answers. The doesn't stop it from being the case. 0 multiplied by infinity is also equal to 1 (which can be seen in delta functions - which have infinite height, zero width and an area of unity - I used to have to use them all the time for Fourier, Laplace and Z Transforms).

nope. any number, even infinity, multiplied by 0 is 0. If the text I bolded would be true, then a line (1d) which has infinite length would be a 2d figure. Not happening.

Also, a calculator could draw a mark for the infinite ( ∞ ), if your statement would be true

0 multiplied by infinity is 1.

http://upload.wikimedia.org/math/e/e/4/ … 47104d.png
http://upload.wikimedia.org/math/1/4/3/ … 85aad2.png

No. a line is not a rectangle.

Last edited by DeathUnlimited (2007-04-02 14:58:37)

if 0 multiplied by infinite is 1, then a line (1d) which has infinite length would be a Rectangle (2d).

Because Lines don't have area.

I won't argue more than that, since you clearly are educated in this more, but that is how I get it.


Afterall I was the one who got the right answer on the first page

Last edited by DeathUnlimited (2007-04-02 15:06:06)

Bertster7 wrote:

DeathUnlimited wrote:

if 0 multiplied by infinite is 1, then a line (1d) which has infinite length would be a Rectangle (2d).

Because Lines don't have area.

I won't argue more than that, since you clearly are educated in this more, but that is how I get it.


Afterall I was the one who got the right answer on the first page

Hope this clears it up a bit.

The Dirac delta or Dirac's delta, often referred to as the unit impulse function and introduced by the British theoretical physicist Paul Dirac, can usually be informally thought of as a function δ(x) that has the value of infinity for x = 0 and the value zero elsewhere. The integral of the Dirac delta from any negative limit to any positive limit is 1.

The integral is essentially the area.

It's not a rectangle or a line. It's an inconceivable thing that could never exist - it's just a mathematical concept that is usefull for solving stuff.

Oooo-kay.. clear now..

_{*hides in a corner ashamed of his fighting for nothing*}

0 * infinity is NOT 1...
0 * infinity is the same as InfinityX / (1 / 0) = InfinityX/InfinityY

This is only 1 if infinityX = infinityY
WHICH is rarely the case.

The limit of this problem could also be 2 or 3. Just use L'Hopital to find out.

damn Ryan ure good......but no the fundamental error of this problem was already stated by DeathUlimited u cant have x=1 AND x+1=1 because its "x" in both cases and if x=1 then u replace ure "x" to get 1+1=1 which only takes a grade 2 kid to know is wrong.

How did this go to using calculus 2 and integrals to find area?

De_Jappe wrote:

0 * infinity is NOT 1...
0 * infinity is the same as InfinityX / (1 / 0) = InfinityX/InfinityY

This is only 1 if infinityX = infinityY
WHICH is rarely the case.

The limit of this problem could also be 2 or 3. Just use L'Hopital to find out.

The argument Bertster presented is a bit beyond that.

In any case, as per what you posted: If infinity = 1/0, then 0*(1/0) = 1.

Canadian_Sniper_X wrote:

p.s. I don't know if anyone already mentioned this but INFINITE is a CONCEPT. Not a number. So you cannot apply simple algebra to it.

that's what a few of us have been saying all along.

Masques wrote:

De_Jappe wrote:

0 * infinity is NOT 1...
0 * infinity is the same as InfinityX / (1 / 0) = InfinityX/InfinityY

This is only 1 if infinityX = infinityY
WHICH is rarely the case.

The limit of this problem could also be 2 or 3. Just use L'Hopital to find out.

The argument Bertster presented is a bit beyond that.

In any case, as per what you posted: If infinity = 1/0, then 0*(1/0) = 1.

Dude, read my post, infinity is NOT the same as infinity in another example.
0* infinity is NOT defined (just as infinity/infinity). Please go back to school, We have learned that here when I was 15 oke?
You have to use the rule of l'hopital depending on the problem to find out what the limit is.
Oke so please grab a math book before trying to convince me the other way.

Or to make it easier to understand:
1/0 = infinity
2/0 = infinity
3/0 = infinity
10/0 = infinity

So 0*infinity is NOT always 0*(1/0), therefor 0*infinity is not 1, but NOT DEFINED. It depends on each problem.

Last edited by De_Jappe (2007-04-03 06:21:00)

De_Jappe wrote:

Masques wrote:

De_Jappe wrote:

0 * infinity is NOT 1...
0 * infinity is the same as InfinityX / (1 / 0) = InfinityX/InfinityY

This is only 1 if infinityX = infinityY
WHICH is rarely the case.

The limit of this problem could also be 2 or 3. Just use L'Hopital to find out.

The argument Bertster presented is a bit beyond that.

In any case, as per what you posted: If infinity = 1/0, then 0*(1/0) = 1.

Dude, read my post, infinity is NOT the same as infinity in another example.
0* infinity is NOT defined (just as infinity/infinity). Please go back to school, We have learned that here when I was 15 oke?
You have to use the rule of l'hopital depending on the problem to find out what the limit is.
Oke so please grab a math book before trying to convince me the other way.

Or to make it easier to understand:
1/0 = infinity
2/0 = infinity
3/0 = infinity
10/0 = infinity

So 0*infinity is NOT always 0*(1/0), therefor 0*infinity is not 1, but NOT DEFINED. It depends on each problem.

I agree, I was told a few months ago my my maths teacher that anything divided by 0 is undefined, not infinity

But, keep in mind, when taking the limit of something that yields expression/0, you will get infinity as your answer.

Last edited by heggs (2007-04-03 07:56:30)

The Magic Mullet wrote:

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