What's wrong with this? Answer = Karma

2007-04-03 10:02:32

#51

r'Eeee: That's how I roll, BITCH!; +311|6904

x=1 and x^2=1
x= (1)^(1/2) or square root of 1

So basically you got the same equations i.e. x=1

Equal them and you get 1=1

http://i103.photobucket.com/albums/m144 … titled.jpg

Damn, I spend doing maths, even in my break time!

Last edited by rabee2789b (2007-04-03 10:08:45)

2007-04-03 10:04:59

#52

BakaBakaNeko2: Sniper Kitten Wins !; +16|6750|Malaysia

*tries dividing by zero*

*head asplodes*

2007-04-03 10:55:12

#53

topal63: . . .; +533|7174

Canadian_Sniper_X wrote:
(Note x^2 is 'x squared')
x = 1 x^2 = 1
x = x^2
x - 1 = x^2 - 1
(x - 1) = (x - 1)(x + 1)
(x - 1)/(x - 1) = (x - 1)(x + 1)/(x - 1)
1 = x + 1

therefore 1 = 2

or my skills in paint.
http://img511.imageshack.us/img511/2885 … ooflb5.jpg

What's wrong with your answer - is what is wrong with your formula.

When x=1; of course x=1 and x^2=1. That is true., when x=0, x^2=0 as well, in these two cases x = x^2; beyond this it will be false because this is not an identity formula in any mathematics I know of:

That x=x^2,

. . . this is a false statement. As when x=2; of course x=2 and x^2=4, and of course 2 does not equal 4.

You can even say (speak) the obvious error:

One one is one.
Zero zeros are zero.
Two twos are four.

Note: It is wrong because of this false statement, and for no other reason, you need not look any further: x = x^2 is FALSE as a rule.

Last edited by topal63 (2007-04-03 11:04:04)

2007-04-03 11:00:15

#54

UnknownRanger: Squirrels, natures little speedbump.; +610|6801|Cali

Nessie09 wrote:
DeathUnlimited wrote:
(x - 1)/(x - 1) = (x - 1)(x + 1)/(x - 1)

You can't divide by zero
Yes that is probably where it goes wrong.

2007-04-03 11:15:27

#55

PluggedValve: Member; +17|6796

Bertster7 wrote:
DeathUnlimited wrote:
Bertster7 wrote:
Of course it is. A calculator can't deal with infinite answers. The doesn't stop it from being the case. 0 multiplied by infinity is also equal to 1 (which can be seen in delta functions - which have infinite height, zero width and an area of unity - I used to have to use them all the time for Fourier, Laplace and Z Transforms).
nope. any number, even infinity, multiplied by 0 is 0. If the text I bolded would be true, then a line (1d) which has infinite length would be a 2d figure. Not happening.

Also, a calculator could draw a mark for the infinite ( ∞ ), if your statement would be true
0 multiplied by infinity is 1.

http://upload.wikimedia.org/math/e/e/4/ … 47104d.png
http://upload.wikimedia.org/math/1/4/3/ … 85aad2.png

What happened to anything times by 0 = 0 ??

2007-04-03 11:18:34

#56

Superslim: BF2s Frat Brother; +211|7147|Calgary

DeathUnlimited wrote:
(x - 1)/(x - 1) = (x - 1)(x + 1)/(x - 1)

You can't divide by zero

so (x-1)/(x-1) is not 1

2007-04-03 11:22:13

#57

DUnlimited: got any popo lolo intersting?; +1,160|6919|cuntshitlake

Superslim wrote:
DeathUnlimited wrote:
(x - 1)/(x - 1) = (x - 1)(x + 1)/(x - 1)

You can't divide by zero

so (x-1)/(x-1) is not 1

Yes, this is already forgotten and gone, I won, and I have been rewarded

Last edited by DeathUnlimited (2007-04-03 11:22:42)

main battle tank karthus medikopter 117 megamegapowershot gg

2007-04-03 11:24:10

#58

r'Eeee: That's how I roll, BITCH!; +311|6904

DeathUnlimited wrote:
Superslim wrote:
DeathUnlimited wrote:
(x - 1)/(x - 1) = (x - 1)(x + 1)/(x - 1)

You can't divide by zero

so (x-1)/(x-1) is not 1
Yes, this is already forgotten and gone, I won, and I have been rewarded

He didn't divide by zero, did he?

and (x-1)/(x-1) is one

Last edited by rabee2789b (2007-04-03 11:24:58)

2007-04-03 11:46:56

#59

DUnlimited: got any popo lolo intersting?; +1,160|6919|cuntshitlake

rabee2789b wrote:
He didn't divide by zero, did he?

and (x-1)/(x-1) is one

x is 1

then x-1 is 0

then 0/0 is not 1

main battle tank karthus medikopter 117 megamegapowershot gg

2007-04-03 11:50:53

#60

Fredrik: i hate you all; +201|7104|Norway

wow 3 pages...

1^2 = 1

Therefore x = 1

2007-04-03 13:01:10

#61

r'Eeee: That's how I roll, BITCH!; +311|6904

DeathUnlimited wrote:
rabee2789b wrote:
He didn't divide by zero, did he?

and (x-1)/(x-1) is one
x is 1

then x-1 is 0

then 0/0 is not 1

x=1 is the value of x. x-1 is a factor! You get that be taking -1 from both side.

When you are saying x-1=0 . You are solving x and getting the value, and if u look at the graph of x=1 its a vertical line parallel to the y-axis!

I don't really understand the idea of 0/0?

I guess ur saying the value of x=0? which is not really right!

Last edited by rabee2789b (2007-04-03 13:06:39)

2007-04-03 18:21:24

#62

Canadian_Sniper_X: Member; +45|6945|Kamloops, BC Canada

PEOPLE!! STFU! Death got it right. That's the ONLY thing wrong with the proof.

That's IT!! there's nothing else!!

If x=1 then x^2=1... IT'S VALID. (the converse is not necessarily true... but I didn't state the converse. Some people are acting like I have though.)

x = x^2 IS VALID WHEN THEY BOTH EQUAL 1!!!

And... for you who don't seem to understand (See post above me)

IF x=1... THEN x-1=0... ALL you are doing is 'plugging' in the value of x.

It's stated that x=1... you are not solving for x. x is already solved.

If you disagree with me, then you have no idea what you are talking about and will only look foolish if you argue.

BF2S Forums What's wrong with this? Answer = Karma

Canadian_Sniper_X wrote:

Nessie09 wrote:

DeathUnlimited wrote:

Bertster7 wrote:

DeathUnlimited wrote:

Bertster7 wrote:

DeathUnlimited wrote:

Superslim wrote:

DeathUnlimited wrote:

DeathUnlimited wrote:

Superslim wrote:

DeathUnlimited wrote:

rabee2789b wrote:

DeathUnlimited wrote:

rabee2789b wrote:

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