Me too, although is such a long time since I was at school. Must be a British thing.Phaytal wrote:
I always remembered it ass
O A O
S H C H T A
O = Opposite, A = Adjacent, S/C/T = The angle or whatever, so you fill in the 2 you have and follow the triangle rules
That's the easiest way to remember it. Soh cah toa.Phaytal wrote:
I always remembered it ass
O A O
S H C H T A
O = Opposite, A = Adjacent, S/C/T = The angle or whatever, so you fill in the 2 you have and follow the triangle rules
Sin opposite hypotenuse
Cos adjacent hypotenuse
Tan opposite adjacent
You know, in all my math up through differential equations, and all my physics classes and engineering classes....
I think I have used law of cosines.... 3 times? (and all when I was taking trig)
The double angle formula 4 times, and law of sine 8 times... But law of sine is easy to remember since its just the ratio of a side, and the sine of the opposite angle is equal to the ratio of any other side and the sine of its opposite angle...
Just remember that x^2+y^2=1
cos = x
sin = y
tan = slope = y/x
Thats all the trig you REALLY need
I think I have used law of cosines.... 3 times? (and all when I was taking trig)
The double angle formula 4 times, and law of sine 8 times... But law of sine is easy to remember since its just the ratio of a side, and the sine of the opposite angle is equal to the ratio of any other side and the sine of its opposite angle...
Just remember that x^2+y^2=1
cos = x
sin = y
tan = slope = y/x
Thats all the trig you REALLY need
Last edited by VicktorVauhn (2008-08-22 14:48:07)
I'm on independent study maths so i get to sit in a corner of the 6th period calculus class and help kids with their work
fun tbh
fun tbh
shoulda fucking listened then eh.. SHOULDNT YOU!!?!?!?haffeysucks wrote:
Help me bf2s, I can't remember Geometry for shit
http://i131.photobucket.com/albums/p292 … 081302.jpg
What he said.DesertFox- wrote:
Law of Cosines (as taken from my Pre-Calculus notes)
c2 = a2 + b2 - 2ab(cos γ)
*Note: γ is angle directly opposite c side. The formula can be changed to suit the a or b sides as well. Basically, just use the above as an example, where you use c and gamma together, a and alpha, and b and beta. Other than that, you should be able to make it work.
Answer should be 16.8 if I did it right.
Last edited by Jestar (2008-08-22 17:41:53)
dammit why does everyone ignore my answer
Last year one teacher let everyone know they could remember Soh Cah Toa by thinking Some old hippy caught another hippy tripping on acid.
I remember SOH CAH TOA, but that doesn't help me. I see a lot of formula answers here but I'm too tired to think right now, I'll check it out tomorrow and award karmaz
"people in ny have a general idea of how to drive. one of the pedals goes forward the other one prevents you from dying"
Can you tell us what the numbers are? I'll solve it but I need the numbers I cant read them in your pic.
Last edited by GorillaKing798 (2008-08-22 20:32:16)
8, 105, 13GorillaKing798 wrote:
Can you tell us what the numbers are? I'll solve it but I need the numbers I cant read them in your pic.
"people in ny have a general idea of how to drive. one of the pedals goes forward the other one prevents you from dying"
Wow awesome timing my calculator just died, sorry man.
Let's work through it, anyway, shall we?Jestar wrote:
What he said.DesertFox- wrote:
Law of Cosines (as taken from my Pre-Calculus notes)
c2 = a2 + b2 - 2ab(cos γ)
*Note: γ is angle directly opposite c side. The formula can be changed to suit the a or b sides as well. Basically, just use the above as an example, where you use c and gamma together, a and alpha, and b and beta. Other than that, you should be able to make it work.
Answer should be 16.8 if I did it right.
Assuming the above formula is correct for this situation (it is), we start off with plugging in the variables.
c2 = 82 + 132 - 2(8)(13)(cos 105°)
Then we simplify it.
c2 = 64 + 169 - 208(cos 105°)
Simplify further.
c2 = 233 - 208(cos 105°)
Now let's get rid of those pesky parentheses.
c2 = 233 - 208(-.258819045)
And simplify it.
c2 = 233 - (-53.83436138)
Finally, group those two (normally we'd do all this jazz on the calculator, but for the purpose of BF2s, screw rounding)
c2 = 286.8343614
Therefore:
c = √286.8343614 = 16.93618497
Last edited by DesertFox- (2008-08-23 06:57:30)
lol they are all the same formula... Its the law of cosine, the problem tells you specifically what exact formula you need to use, and gives you all the variable needed to solve it in standard form....haffeysucks wrote:
I remember SOH CAH TOA, but that doesn't help me. I see a lot of formula answers here but I'm too tired to think right now, I'll check it out tomorrow and award karmaz
You had the forumula down wrong. It's subtract 2ab(cosx)DesertFox- wrote:
Hmmm, I got 13.4 (actually 13.38527693)Jestar wrote:
What he said.DesertFox- wrote:
Law of Cosines (as taken from my Pre-Calculus notes)
c2 = a2 + b2 - 2ab(cos γ)
*Note: γ is angle directly opposite c side. The formula can be changed to suit the a or b sides as well. Basically, just use the above as an example, where you use c and gamma together, a and alpha, and b and beta. Other than that, you should be able to make it work.
Answer should be 16.8 if I did it right.
Let's work through it, shall we?
Assuming the above formula is correct for this situation (it is), we start off with plugging in the variables.
c2 = 82 + 132 + 2(8)(13)(cos 105°)
Then we simplify it.
c2 = 64 + 169 + 208(cos 105°)
Simplify further.
c2 = 233 + 208(cos 105°)
Now let's get rid of those pesky parentheses.
c2 = 233 + 208(-.258819045)
And simplify it.
c2 = 233 + (-53.83436138)
Finally, group those two (normally we'd do all this jazz on the calculator, but for the purpose of BF2s, screw rounding)
c2 = 179.1656386
Therefore:
c = √179.1656386 = 13.38527693 = 13.4