Finray
Hup! Dos, Tres, Cuatro
+2,629|6197|Catherine Black
Did nobody teach you the STD triangle?

  D
S-T

Distance = SpeedxTime
Speed = Distance/Time
Time = Distance/Speed

hurr
https://i.imgur.com/qwWEP9F.png
Peter
Super Awesome Member
+494|6810|dm_maidenhead

-Sh1fty- wrote:

Ok but what about the bicycle problem? I'm still sort of lost. Minty helped but I'm still confused.


A cyclist leaves the town of Ouchy towards Cully at 15:00. His average speed is 18km/h. Another man is walking from Cully to Ouchy and he leaves at 14:30. His average speed is 7.2km/h.

The distance separating the two towns is 10km.
I'm so freaking bad at this. T = time right? So what the hell does 72t mean? 72 * t?

No way I'm ever passing this fucking school, why did I ever take these extra courses? I just wanted to finish a year earlier...
https://i45.tinypic.com/21lv4hx.png
presidentsheep
Back to the Fuhrer
+208|6369|Places 'n such
s = ut+0.5at2
s = vt-0.5at2
s = 0.5(u+v)t
v = u+at
v2 = u2+2as
a = (v-u)/t

a=acceleration, t=time, u=initial velocity, v= final velocity, s=displacement.

Only equations you'll ever need. ever.

edit:fucking smilies.

Last edited by presidentsheep (2010-02-25 15:07:04)

I'd type my pc specs out all fancy again but teh mods would remove it. Again.
Bevo
Nah
+718|6929|Austin, Texas

-Sh1fty- wrote:

Uhhh yeah well here's another exercise I've got to do, this one is with bikes, maybe this'll help.

A cyclist leaves the town of Ouchy towards Cully at 15:00. His average speed is 18km/h. Another man is walking from Cully to Ouchy and he leaves at 14:30. His average speed is 7.2km/h.

The distance separating the two towns is 10km.


The question is:

At what time and what distance from Ouchy will they cross each other?
right so given t=time

let t=0 be 15:00. Time is 0 at 15:00.



We'll call the first cyclist A. He starts at t=0 and his speed is 18km/h.
We'll call the second cyclist B. He starts at t= -00:30 and his speed is 7.2km/h.

To simplify the problem, have them start at the same time. That means multiply out the distance covered by cyclist B until t=0 for both of them. 7.2km * .5h = 3.6km. The distance between the two cyclists at 15:00 is now 6.4km.

Use the equation from the other problem. 18t + 7.2t = 6.4
Simplify. 25.2t = 6.4km
t = .25397h, or (*60) = 15.24 minutes.

At time = 15:15, the cyclists cross. To find the distance from ouchy, simply multiply the time by the rider leaving ouchy. .25397h*18km/h = 4.57km.


I realized I just reiterated everything peter wrote out, but you seem to have some serious comprehension issues. Talk to your teacher and try to get the basic things sorted out such as variables and forming equations.
Peter
Super Awesome Member
+494|6810|dm_maidenhead
I just looked at my post and remembered how proud I was of my cyclist diagram.
mcminty
Moderating your content for the Australian Govt.
+879|7130|Sydney, Australia

Peter wrote:

I just looked at my post and remembered how proud I was of my cyclist diagram.
That's a good diagram.. almost on par with my train crash
liquidat0r
wtf.
+2,223|7035|UK

Bevo wrote:

I don't think I learned the cross or dot product in HS...

and they certainly wouldn't teach vector multiplication BEFORE simple things like velocity and displacement
Fairly sure I was taught to write x like that in order to avoid confusion in later life.
DrunkFace
Germans did 911
+427|7089|Disaster Free Zone

liquidat0r wrote:

Bevo wrote:

I don't think I learned the cross or dot product in HS...

and they certainly wouldn't teach vector multiplication BEFORE simple things like velocity and displacement
Fairly sure I was taught to write x like that in order to avoid confusion in later life.
Was writing x like that since like 3/4 grade. Cause 7xy =/= 7xy

Last edited by DrunkFace (2010-02-26 00:45:29)

Dilbert_X
The X stands for
+1,822|6514|eXtreme to the maX
Just need to work out the closing speed (=Speed A + Speed B) and the distance travelled.
Fuck Israel
-Sh1fty-
plundering yee booty
+510|5882|Ventura, California
Thanks a lot for your help guys. I'm off to do my test now. I hope I do well, sucks they give me a test right after vacation.
And above your tomb, the stars will belong to us.
VicktorVauhn
Member
+319|6800|Southern California

Finray wrote:

Did nobody teach you the STD triangle?

  D
S-T

Distance = SpeedxTime
Speed = Distance/Time
Time = Distance/Speed

hurr
No one taught me that... and I am glad.
Stupidest thing I have seen in a long time.

Its very very basic algebra. If you need a special triangle to remember how to algebraically manipulate an equation that easy you got MUCH bigger problems.
Spark
liquid fluoride thorium reactor
+874|7083|Canberra, AUS

liquidat0r wrote:

Bevo wrote:

I don't think I learned the cross or dot product in HS...

and they certainly wouldn't teach vector multiplication BEFORE simple things like velocity and displacement
Fairly sure I was taught to write x like that in order to avoid confusion in later life.
yeah, i used to write x as a cross but i eventually became so annoyed because i kept mixing up x and * in like 10xy or 10*y that i decided to do the curly version (although my handwriting is always fairly curly)
The paradox is only a conflict between reality and your feeling what reality ought to be.
~ Richard Feynman
blademaster
I'm moving to Brazil
+2,075|7053

-Sh1fty- wrote:

Thanks a lot for your help guys. I'm off to do my test now. I hope I do well, sucks they give me a test right after vacation.
good luck with the test, wish I could've helped but was never good at physics, I was better at maths... was ok for the most part.....
VicktorVauhn
Member
+319|6800|Southern California

Spark wrote:

liquidat0r wrote:

Bevo wrote:

I don't think I learned the cross or dot product in HS...

and they certainly wouldn't teach vector multiplication BEFORE simple things like velocity and displacement
Fairly sure I was taught to write x like that in order to avoid confusion in later life.
yeah, i used to write x as a cross but i eventually became so annoyed because i kept mixing up x and * in like 10xy or 10*y that i decided to do the curly version (although my handwriting is always fairly curly)
Why would you ever write out 10*y?

Coefficients are pretty much always just written as 10y. I have never seen any text book, assignment, test, hand out, example, ect... written as 10 X Y as in 10 times Y. It's just not done for that very reason.
Spark
liquid fluoride thorium reactor
+874|7083|Canberra, AUS

VicktorVauhn wrote:

Spark wrote:

liquidat0r wrote:


Fairly sure I was taught to write x like that in order to avoid confusion in later life.
yeah, i used to write x as a cross but i eventually became so annoyed because i kept mixing up x and * in like 10xy or 10*y that i decided to do the curly version (although my handwriting is always fairly curly)
Why would you ever write out 10*y?

Coefficients are pretty much always just written as 10y. I have never seen any text book, assignment, test, hand out, example, ect... written as 10 X Y as in 10 times Y. It's just not done for that very reason.
i don't know i just made that up on the spot didn't i? the point is i changed because i was getting x and * mixed up.
The paradox is only a conflict between reality and your feeling what reality ought to be.
~ Richard Feynman
DUnlimited
got any popo lolo intersting?
+1,160|6872|cuntshitlake

presidentsheep wrote:

s = ut+0.5at2
s = vt-0.5at2
s = 0.5(u+v)t
v = u+at
v2 = u2+2as
a = (v-u)/t

a=acceleration, t=time, u=initial velocity, v= final velocity, s=displacement.

Only equations you'll ever need. ever.

edit:fucking smilies.
Unless if you actually study physics on a higher level than junior high. That's just the most basic stuff for mechanics.

Last edited by DeathUnlimited (2010-03-01 04:14:23)

main battle tank karthus medikopter 117 megamegapowershot gg
Gravityy
Member
+8|5724|
while there's a thread for this, i might just lay down my own problem

An athlete, commencing at a point due east, completes a half lap of a 440m track in 25s. Determine the athlete's:
- average velocity (in a westerly direction)
-Sh1fty-
plundering yee booty
+510|5882|Ventura, California
I FAAAAAAAAAAAAAAAAAAAAAAAAAAAAAIIIIIIIIIIILED

No jk

I did ok but just "OK"

That teacher is such a faggot anyway, he loves throwing shit in we never studied, and when we ask for help he says we're young idiots who're too stupid to look stuff up ourselves and cuts us off when we try to explain.

Anyway, fuck him

But yeah I'd like to thank you all for the great help! Without you I would have flunked for sure!
And above your tomb, the stars will belong to us.
VicktorVauhn
Member
+319|6800|Southern California

Gravityy wrote:

while there's a thread for this, i might just lay down my own problem

An athlete, commencing at a point due east, completes a half lap of a 440m track in 25s. Determine the athlete's:
- average velocity (in a westerly direction)
Well, really it depends on where he started and the shape of the track, and how they position NSEW

Assuming North is up and west is left, and the track is round...

You go 180 degrees around the circle, then find the horizantal distance from starting point to finishing point and divide by time.

So if he starts at the top of the track, he makes it to the bottom, and average velocity is 0, because only taking his horizantal motion into consideration he ran off to the side, then back, and the velocity vectors in the second half cancel those in the first.

If he starts at the side of the track, he runs half way around to the other side, and his horizontal motion is equal to the diameter, and velocity is that distance divided by the time it took. If 440m is the circumference the diameter is 440/pi or about 140m/25 to give like 5.6m/s

If his starting point is at some angle Ø from the east-west axis then his displacement is (440/pi)*cos(Ø)/25, which is basically the radius times the cosine of the angle doubled to give the twice the horizontal distance from the center to the starting point divided by the time.
presidentsheep
Back to the Fuhrer
+208|6369|Places 'n such

DeathUnlimited wrote:

presidentsheep wrote:

s = ut+0.5at2
s = vt-0.5at2
s = 0.5(u+v)t
v = u+at
v2 = u2+2as
a = (v-u)/t

a=acceleration, t=time, u=initial velocity, v= final velocity, s=displacement.

Only equations you'll ever need. ever.

edit:fucking smilies.
Unless if you actually study physics on a higher level than junior high. That's just the most basic stuff for mechanics.
Pfffffft, I've nearly finished A-Level's and everything seems to boil down to these equations (Well... Three of them) after a while.
I'd type my pc specs out all fancy again but teh mods would remove it. Again.
Ilocano
buuuurrrrrrppppp.......
+341|7075

presidentsheep wrote:

DeathUnlimited wrote:

presidentsheep wrote:

s = ut+0.5at2
s = vt-0.5at2
s = 0.5(u+v)t
v = u+at
v2 = u2+2as
a = (v-u)/t

a=acceleration, t=time, u=initial velocity, v= final velocity, s=displacement.

Only equations you'll ever need. ever.

edit:fucking smilies.
Unless if you actually study physics on a higher level than junior high. That's just the most basic stuff for mechanics.
Pfffffft, I've nearly finished A-Level's and everything seems to boil down to these equations (Well... Three of them) after a while.
For general physics.  Have fun with quantum theory.

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