Hmmm...What about:Ganko_06 wrote:
Try some Calculus
f(x) = sin(cos(tanx))
Find f'(x)
Mcminty.
Hmmm...What about:Ganko_06 wrote:
Try some Calculus
a2 + b2 = c2Cougar wrote:
a+b=c right?
God I hate math. This thread is like kryptonite to me.
-[[sec(x)]^2]sin(tanx)cos(cos(tanx))mcminty wrote:
Hmmm...What about:Ganko_06 wrote:
Try some Calculus
f(x) = sin(cos(tanx))
Find f'(x)
Mcminty.
WTFeyesteponbabies wrote:
Math in general is not a subject I'm most talented in, though I do appreciate learning about cultures and communication.
May I ask how you got to that answer? I can't see any obvious mistakes in my working, andGanko_06 wrote:
Here's the correct answer:
f'(x) = {[(x+1)(ln(x+1)]2}+(x+1)(ln(x+1)+1}(x+1)^[(x+1)^(x+1)+x]
Imaginary. 4iShadowFoX wrote:
Here is an easy one.
Square root of -16
Last edited by Naughty_Om (2006-10-22 10:49:25)
Ahh so no one did fall for that little trick. Glad to see there are some people on these forums with a noodle.Naughty_Om wrote:
Imaginary. 4iShadowFoX wrote:
Here is an easy one.
Square root of -16
?ShadowFoX wrote:
Ahh so no one did fall for that little trick. Glad to see there are some people on these forums with a noodle.Naughty_Om wrote:
Imaginary. 4iShadowFoX wrote:
Here is an easy one.
Square root of -16
Last edited by Darkhelmet (2006-10-22 13:23:49)