CommieChipmunk
Member
+488|6996|Portland, OR, USA
this is really going out on a limb but i cant find it anywhere else.

How the hell does chrysoberyl (BeAl2O4) form? like its molecular structure?  I've tried everything i can think of and can't get it to work.  It's a Rhombic bipyramidal shape though...

Help! I'll +1 you forever lol
cablecopulate
Member
+449|7164|Massachusetts.
When I had chemistry, the teacher was this short little fat lady. A short-round, if you will. She walked in front of me and tripped on my foot and fell. True story.
Locoloki
I got Mug 222 at Gritty's!!!!
+216|7066|Your moms bedroom
read your chemistry book... noob
Locoloki
I got Mug 222 at Gritty's!!!!
+216|7066|Your moms bedroom
ask jeeves
Locoloki
I got Mug 222 at Gritty's!!!!
+216|7066|Your moms bedroom
CommieChipmunk
Member
+488|6996|Portland, OR, USA
i've been reading it.  i just can't get the electrons right... it like.. doesnt work.  This is AP chem btw, so any of you in college chem........
Locoloki
I got Mug 222 at Gritty's!!!!
+216|7066|Your moms bedroom
CommieChipmunk
Member
+488|6996|Portland, OR, USA
I've seen that, i'm looking for the molecular shape, like what it actually looks like, how its bonded, etc
l41e
Member
+677|7075

Apparently it looks like this.

https://www.ill.fr/dif/3D-crystals/images/icons/chrysoberyl-s.gif

Edit: Source.

Last edited by k30dxedle (2006-11-13 19:34:48)

CommieChipmunk
Member
+488|6996|Portland, OR, USA
yeah i know, i've seen that too, that helps me very little.. thanks for the effort though
Locoloki
I got Mug 222 at Gritty's!!!!
+216|7066|Your moms bedroom
ehhh covalent bond???
l41e
Member
+677|7075

When's your project due? Maybe I can find out some more stuff.
CommieChipmunk
Member
+488|6996|Portland, OR, USA
the Beryllium to Aluminum bond is as covalent as it gets, but either to the oxygen is very ionic.

it's due Wednesday.

Last edited by CommieChipmunk (2006-11-13 19:38:12)

Locoloki
I got Mug 222 at Gritty's!!!!
+216|7066|Your moms bedroom
Beryl (beryllium Aluminium Silicate) is a mineral, which occurs mainly in greisens, pegmatite and hydrothermal deposits. Chemically the mineral can be expressed as Be3Al2(SiO3)6. It crystallizes in the hexagonal system. Cat ion replacements give rise to various colours and hence varieties or types of the mineral. Most common varieties of beryl in Zimbabwe are: the industrial or common variety which is non transparent and may be green, white, blue or brownish and the gemstones varieties -: emerald (green), aquamarine (blue), heliodor (golden yellow) and goshenite (colourless). Coloured beryl exhibit weak to distinct dichroism. The gemstones varieties are used for adornment in jewellery settings.
CommieChipmunk
Member
+488|6996|Portland, OR, USA
thats beryl dude, thats called "beryllium aluminum silicate"  I'm looking for chrysoberyl aka alexandrite.  Chrysoberyl and it is beryllium aluminum oxide.  Alexandrite is really a variant where 1 % of the aluminum ions are replaced by chromium...
Pizdets_Velikiy
Member
+8|6829
I'm thinking something like this (hope it comes out):

Al---Al
  \   /
    O
     |
O--Be--O
     |
     O

Keep in mind that it will form a crystal lattice, so my understanding is that you won't end up having naked electrons.
Pizdets_Velikiy
Member
+8|6829

Pizdets_Velikiy wrote:

I'm thinking something like this (hope it comes out):

Al---Al
  \   /
    O
     |
O--Be--O
     |
     O

Keep in mind that it will form a crystal lattice, so my understanding is that you won't end up having naked electrons.
Oh hmm disregard that, because I just realized that beryllium is bivalent, so a single unit looking like that is probably not reasonable. I for some reason thought OH IT'S LIKE PHOSPHATE and stuck four oxygens on it. Don't ask why.

How about this:

O--Al--Be--Al--O
      |          |
     O          O

Seems to work for valences, though some dipole moments will be questionable. May work out with lattice formation.
CommieChipmunk
Member
+488|6996|Portland, OR, USA

Pizdets_Velikiy wrote:

Pizdets_Velikiy wrote:

I'm thinking something like this (hope it comes out):

Al---Al
  \   /
    O
     |
O--Be--O
     |
     O

Keep in mind that it will form a crystal lattice, so my understanding is that you won't end up having naked electrons.
Oh hmm disregard that, because I just realized that beryllium is bivalent, so a single unit looking like that is probably not reasonable. I for some reason thought OH IT'S LIKE PHOSPHATE and stuck four oxygens on it. Don't ask why.

How about this:

O--Al--Be--Al--O
      |          |
     O          O

Seems to work for valences, though some dipole moments will be questionable. May work out with lattice formation.
wait, how do the Als make double bonds to Be O and O and they only have 3 electrons?
Pizdets_Velikiy
Member
+8|6829
I have no text book next to me at the moment, and it's been a while since I touched chemistry that isn't organic chemistry, but as far as I remember aluminum has a valence of 3, which means it can bond to three other atoms. It does have 3 electrons in the valence shell, but it will share each one with another one from another atom, forming a covalent bond.

In other words, 2 electrons = covalent bond, but only one of the pair comes from the aluminum. So in my structure, it will yoink two from the oxygens and one from the beryllium. The first structure was wrong because beryllium only has 2, so it could not form three bonds.

This one is of course hypothetical, I can't vouch for it, but it seems SORT of reasonable....
[TUF]Whiskey_Oktober
mmmm...Toasty!
+91|7148|Oregon
they are not dbl bonds...just no way to make a line like that without the double hyphens. i too am in AP chem this year, and i tried it: 32 val e-, that lewis structure is correct...throw lone-pairs where there is not a bond, and boom, 32 e-.
Pizdets_Velikiy
Member
+8|6829
Thank you I forgot to mention that they're not double bonds... ---- stood for a single bond. Are you saying my second one was correct? Because I'm pretty sure the first one isn't.
CommieChipmunk
Member
+488|6996|Portland, OR, USA
there are only 30 valence electrons, but there are no double bonds?  Does it not follow the octet rule or am i not thinking right?

If the oxygen and Al only make a single bond, then there is an unpaired electron on the oxygen? what does that do?

Last edited by CommieChipmunk (2006-11-13 20:21:46)

[TUF]Whiskey_Oktober
mmmm...Toasty!
+91|7148|Oregon
yes, the second one is right....with the 2 Al's bonded to the Be.
[TUF]Whiskey_Oktober
mmmm...Toasty!
+91|7148|Oregon
32 val e-....

Al ...2x3= 6

Be ...1x2= 2

O ...4x6= 24


Total: 32 val e-
CommieChipmunk
Member
+488|6996|Portland, OR, USA
whoa bad math, my bad... shit

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